For Constant Mass

on a particle is, thus, equal to rate change of momentum of the particle without time. Generally mass of the object under consideration is constant and thus cone  be taken out of the derivative:

{\displaystyle {\begin{aligned}{\vec {F}}&=m{\frac {d{\vec {v}}}{dt}}\\{\vec {F}}&=m{\vec {a}}\end{aligned}}} {\displaystyle {\begin{aligned}{\vec {F}}&=m{\frac {d{\vec {v}}}{dt}}\\{\vec {F}}&=m{\vec {a}}\end{aligned}}}

For constant mass,

{\displaystyle {\vec {F}}=m{\vec {a}}}

{\displaystyle {\vec {F}}=m{\vec {a}}}

Force is equal to mass times acceleration. This version of Newton’s Second Law of Motion assumes which the mass of the body does not change without time, and as such, does not represent a general mathematical form of the Law. Consequently, this equation cannot, for example, be applied to the motion of a rocket, which loses its mass (the lost mass is ejected at the rear of the rocket) without the passage of time.

It makes sense which the direction of the acceleration is in the direction of the resultant force. If you push something away from you it doesn’t move toward you unless of course there is another force acting on the object towards you!

Give us a chance to draw an unpleasant sketch of the circumstance 

In an unpleasant sketch one ought to incorporate the majority of the data given in the issue. The majority of the sizes of the relocations are appeared and a compass has been incorporated as a kind of perspective heading. 

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Stage 2 : 

Next we pick a scale for our vector chart. It is obvious from the harsh sketch which picking a scale where 1cm speaks to 1km (scale: 1cm = 1km) would be a decent decision in this issue )- the chart will at that point take up a decent division of one A4 page. We presently begin the exact development. 

Stage 3 : 

Development Step 1: Starting at the harbor H we draw the main vector 6cm long toward the path north (recall in the graph 1cm speaks to 1km): 

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Development Step 2: Since the ship is currently at port A we draw the second vector 12cm long beginning starting here toward the path east: hich {\displaystyle 2\times 2} {\displaystyle 2\times 2} is only 2 gatherings of 2 included to give 4. We cone embrace a comparative way to deal with see how vector duplication functions. 

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